package com.jia.leetCode;

/**
 * ActorDirector 表：

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| actor_id    | int     |
| director_id | int     |
| timestamp   | int     |
+-------------+---------+
timestamp 是这张表的主键.
 

写一条SQL查询语句获取合作过至少三次的演员和导演的 id 对 (actor_id, director_id)

示例：

ActorDirector 表：
+-------------+-------------+-------------+
| actor_id    | director_id | timestamp   |
+-------------+-------------+-------------+
| 1           | 1           | 0           |
| 1           | 1           | 1           |
| 1           | 1           | 2           |
| 1           | 2           | 3           |
| 1           | 2           | 4           |
| 2           | 1           | 5           |
| 2           | 1           | 6           |
+-------------+-------------+-------------+

Result 表：
+-------------+-------------+
| actor_id    | director_id |
+-------------+-------------+
| 1           | 1           |
+-------------+-------------+
唯一的 id 对是 (1, 1)，他们恰好合作了 3 次。

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/actors-and-directors-who-cooperated-at-least-three-times
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 * @author Administrator
 *
 */
public class Pro1050 {
//select actor_id,director_id from ActorDirector group by actor_id,director_id having count(actor_id) >=3;
}
